Even the Nevada Gaming Control Board will uphold dubious actions by casinos: http://www.sweatthemoney.com/sands1.html, so what hope is there for Malta?

Even the Nevada Gaming Control Board will uphold dubious actions by casinos: http://www.sweatthemoney.com/sands1.html, so what hope is there for Malta?The Sands Regency is Reno's answer to vegas' El Cortez... it is a seedy place full of desperate gamblers. The compainant should definitely appeal the ruling!
Not to distract, but here's (http://www.youtube.com/watch?v=XFj_1F6R52s) another unsettled million dollar rip-off in vegas with corelations to the interwetten situ.

Edit: Oops, I see MS has this up at the sweatthemoney too. Link (http://www.sweatthemoney.com/fiestahenderson1.html)

The D9 decision is correct. It's not the first incidence of this I've heard. For the deuce to make 21 the initial hand must be considrd a 19, which cannot be doubled in D9, only in DOA. It has no effect on the house edge.

So the premise would be that the player can only double on 9-10-11 and as he chose to, that decision made the A=one?


i think that is incorrect as:




2.2: Values of the cards

In blackjack, the cards are valued as follows:
An Ace can count as either 1 or 11, as demonstrated below ... The Ace can be counted as either 1 or 11. You need not specify which value the Ace has. It's assumed to always have the value that makes the best hand.




But that is just my opinion, obviously not the NGC at this point :)

So the premise would be that the player can only double on 9-10-11 and as he chose to, that decision made the A=one?

That's correct. To value the ace as 11 would make 19, which couldn't be doubled. To double A/8 in D9 the ace must be valued as 1.

Anyway, we drift OT.

This deviation from the general rule that A can count as 1 or 11 whichever is better for the player should have been pointed out to the player.

FWIW, Chartwell single deck blacjack (double on 9-11) lets you double on soft 19. I have not been able to check what happens if if you draw an A or 2.

That's correct. To value the ace as 11 would make 19, which couldn't be doubled. To double A/8 in D9 the ace must be valued as 1.

Anyway, we drift OT.

On the other hand if you assume that Ace always has two values 1/11 (like often is intrepreted) then the player doubles on 9/19 and receives 11/21. We simply choose the better of these alternatives, meaning 9 and 21 respectively.